Exercise 1:
What do you find?
We see that these two bisectors are perpendicular.
Exercise 2:
We note that the three bisectors of a triangle are concurrent.
Exercise 3:
What is the nature of triangle ABC?
Explain why.
Any point on a bisector of a segment is equidistant (at the same distance) from the ends of the segment.
Thus CA = CB so the triangle ABC is isosceles in C.
Exercise 4:
1) AD=DC likewise AB=BC
therefore points B and D are equidistant from the ends A and C of the segment [AC]
we deduce that B and D are the bisector of the segment [AC].
2) The line (BD) is the perpendicular bisector of the segment [AB].
Exercise 5:
1) The line is perpendicular to [MN] and passes through its center
so it is the bisector of the segment [MN].
2) A is on the bisector of the segment [MN], so it is equidistant from the vertices M and N.
AN=AM= 5 cm.
Exercise 6:
The lines (d) and (d ‘) are perpendicular to the same line (AC) so
they are parallel to each other.
Exercise 7:
a) The line (d) is not perpendicular to the segment so it is not its perpendicular bisector.
b) The line (d) does not pass through the middle of the segment so it is not its perpendicular bisector.
c) The right (d) is perpendicular to the segment [AB] and passes through its middle, so it is its perpendicular bisector.
d) The line (d) is not perpendicular to the segment so it is not its perpendicular bisector.
e) The right (d) does not pass through the middle of the segment so it is not its perpendicular bisector.
The answers to the math exercises on the median in 6th grade in PDF.
After looking at the answers to these 6th grade math exercises on the perpendicular bisector of a segment and constructions in 6th grade, you can return to the 6th grade exercises.
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