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Rational Functions and Their Graphs: Algebra 2 Math Lesson – PDF Download

    Rational Functions and Their Graphs – Algebra 2 math lesson

    A rational function is a quotient of two polynomials, such as f(x) = 2/(x – 3) + 1. Its graph can have vertical asymptotes where the denominator is zero, a horizontal asymptote that shows end behavior, and holes where factors cancel. Inverse variation, y = k/x, is the simplest model.

    Algebra 2Common Core: F-IF.C.7d · F-IF.B.4

    Key facts:

    • Standards F-IF.C.7d and F-IF.B.4: graph rational functions and identify asymptotes, intercepts, domain and end behavior.
    • The graph of \(y=\frac{a}{x-h}+k\) has asymptotes \(x=h\) and \(y=k\) and center \((h,k)\).
    • A canceled factor \(x-c\) leaves a hole at \(x=c\); a factor that remains in the denominator gives a vertical asymptote.
    • Compare degrees: smaller numerator gives \(y=0\), equal degrees give the ratio of leading coefficients, larger numerator gives none.
    • Inverse variation \(y=\frac{k}{x}\) means the product \(xy\) is constant.

    What is a rational function?

    A rational function is a quotient of two polynomials, \(f(x)=\frac{p(x)}{q(x)}\), where \(q(x)\neq 0\). The simplest one is \(y=\frac{1}{x}\). Its domain is every real number except the zeros of the denominator, and its graph is a hyperbola with two separate branches.

    −6−5−4−3−2−1123456−6−5−4−3−2−11234560xy(1, 1)(-1, -1)
    The parent rational function \(y=\frac{1}{x}\) has two branches and the dashed asymptotes \(x=0\) and \(y=0\).

    How do you find vertical and horizontal asymptotes?

    Vocabulary

    Vertical asymptote: a line \(x=c\) that the graph approaches but never touches. It occurs where the denominator is zero after common factors are removed.

    Horizontal asymptote: a line \(y=L\) that the graph approaches as \(x\) gets very large or very negative.

    Hole: a single missing point that comes from a factor canceled in the numerator and denominator.

    Compare the degrees of the numerator and denominator to find the horizontal asymptote.

    Degrees Horizontal asymptote Example
    Numerator smaller \(y=0\) \(\frac{3}{x^{2}+1}\) gives \(y=0\)
    Degrees equal ratio of leading coefficients \(\frac{6x+1}{2x-5}\) gives \(y=3\)
    Numerator larger none \(\frac{x^{2}+1}{x-1}\) has none

    How do you graph y = a/(x – h) + k?

    This form is \(y=\frac{1}{x}\) stretched by \(a\), moved right \(h\) and up \(k\). The asymptotes are \(x=h\) and \(y=k\), and they cross at the center \((h,k)\). If \(a>0\) the branches lie up-right and down-left of the center; if \(a< 0\) they are reversed.

    1. Draw dashed lines \(x=h\) and \(y=k\).
    2. Make a table with \(x\)-values on both sides of \(h\).
    3. Plot the points and sketch each branch toward the asymptotes.

    Worked example. Graph \(y=\frac{2}{x-3}+1\). The asymptotes are \(x=3\) and \(y=1\). Then \(x=4\) gives \(3\), \(x=5\) gives \(2\), \(x=2\) gives \(-1\) and \(x=1\) gives \(0\).

    −3−2−1123456789−4−3−2−11234560xy(4, 3)(5, 2)(2, -1)(1, 0)x = 3y = 1
    Graph of \(y=\frac{2}{x-3}+1\). The asymptotes cross at the center \((3,1)\), and the branches sit in the upper right and lower left.

    What is a hole in a graph?

    Factor first. For \(f(x)=\frac{x^{2}-4}{x-2}=\frac{(x-2)(x+2)}{x-2}\), the factor \(x-2\) cancels, so the graph is the line \(y=x+2\) except at \(x=2\). The hole is at \((2,4)\), and there is no vertical asymptote there.

    −4−3−2−1123456−2−1123456780xyhole (2, 4)(0, 2)(-2, 0)
    The graph of \(f(x)=\frac{x^{2}-4}{x-2}\) is the line \(y=x+2\) with a hole at \((2,4)\).

    What is inverse variation?

    Two quantities vary inversely when \(y=\frac{k}{x}\), or \(xy=k\), for a constant \(k\neq 0\). If \(y=3\) when \(x=4\), then \(k=12\), and \(y=\frac{12}{x}\) gives \(y=2\) when \(x=6\).

    246810121424681012140xy(1, 12)(2, 6)(3, 4)(6, 2)(12, 1)
    Inverse variation \(y=\frac{12}{x}\): every point has product \(xy=12\), so doubling \(x\) cuts \(y\) in half.

    Rational Functions and Their Graphs: frequently asked questions

    How do you find the vertical asymptote of a rational function?

    Factor the numerator and denominator and cancel common factors. Set each remaining factor of the denominator equal to zero. For \(y=\frac{5}{x+7}\) the vertical asymptote is \(x=-7\).

    What is the difference between a hole and a vertical asymptote?

    Both occur where the denominator is zero. A hole comes from a factor that cancels, so only one point is missing. An asymptote comes from a factor that stays in the denominator, so the graph rises or falls without bound.

    How do you find a horizontal asymptote?

    Compare the degrees of the numerator and denominator. If the numerator has the smaller degree, the asymptote is \(y=0\). If the degrees are equal, divide the leading coefficients, so \(\frac{6x+1}{2x-5}\) has \(y=3\).

    What is the domain of a rational function?

    The domain is all real numbers except the values that make the denominator zero in the original expression, including values that create a hole. For \(\frac{x+1}{x^{2}-9}\) the domain excludes \(x=3\) and \(x=-3\).

    How do you know if a situation is inverse variation?

    Multiply paired values. If \(xy\) gives the same number every time, the relationship is \(y=\frac{k}{x}\). A trip of 240 miles has time \(t=\frac{240}{r}\), because speed times time is always 240.

    See every chapter on the Algebra 2 math page.

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