Mathovore, everything you need to succeed in math: Common Core lessons, worksheets, tests and quizzes
Skip to content

Adding and Subtracting Integers and Rational Numbers: Grade 7 Math Worksheet Answer Key – PDF Download

    Adding and Subtracting Integers and Rational Numbers – Grade 7 math worksheet answer key

    Each solution below shows the full work for the adding and subtracting integers worksheet, including the number line moves and the sign rules used. Compare your steps with these, and check that each answer has the correct sign and units.

    Grade 7Common Core: 7.NS.A.1a · 7.NS.A.1b · 7.NS.A.1c · 7.NS.A.1d

    Problem 1: Opposites and Zero

    The opposite of a number is the same distance from \(0\) on the other side.

    1. \(-9\)
    2. \(15\)
    3. \(-2.5\)
    4. \(0\)

    Since \(-23 + 23 = 0\), the missing number is \(23\).

    Problem 2: Opposites in real life

    1. \(+15\). The opposite is \(-15\): \(15\text{ ft}\) below sea level.
    2. \(-9\). The opposite is \(9\): gaining \(\$9\).
    3. \(-6\). The opposite is \(6\): the temperature rises \(6^{\circ}\text{F}\).

    Opposites are the same distance from \(0\) on opposite sides.

    (a) \(15\) and \(-15\). (b) \(-9\) and \(9\). (c) \(-6\) and \(6\).

    Problem 3: Adding on a Number Line

    Move right for a positive number and left for a negative number.

    1. \(-4 + 7 = 3\)
    2. \(-4 + (-3) = -7\)
    3. \(-4 + 4 = 0\)
    4. \(-4 + (-6) = -10\)
    −10−9−8−7−6−5−4−3−2−1012345678910+7
    Part (a): \(-4 + 7 = 3\).

    Answers: 3, \(-7\), 0, \(-10\).

    Problem 4: Jumping from three

    Adding a negative number moves left. Subtracting a positive number moves left. Subtracting a negative number moves right.

    1. \(3 + (-8) = -5\)
    2. \(3 – 6 = 3 + (-6) = -3\)
    3. \(3 – (-4) = 3 + 4 = 7\)
    -8-7-6-5-4-3-2-10123456788 left4 rightstart
    From \(3\): 8 units left reaches \(-5\); 4 units right reaches \(7\).

    (a) \(-5\). (b) \(-3\). (c) \(7\).

    Problem 5: Adding Integers

    1. Different signs: \(9 – 4 = 5\), keep the negative sign. \(-9 + 4 = -5\).
    2. \(11 – 6 = 5\), keep the negative sign. \(6 + (-11) = -5\).
    3. Same signs: \(7 + 5 = 12\), negative. \(-7 + (-5) = -12\).
    4. Opposites: \(15 + (-15) = 0\).
    5. \(35 – 20 = 15\), positive. \(-20 + 35 = 15\).

    Answers: \(-5\), \(-5\), \(-12\), 0, 15.

    Problem 6: More sums of integers

    1. Same signs: \(13 + 8 = 21\), so the sum is negative. \(-13 + (-8) = -21\).
    2. Different signs: \(17 – 6 = 11\), and \(17\) is larger, so the sum is positive. \(17 + (-6) = 11\).
    3. \(25 – 9 = 16\), and \(-25\) is farther from \(0\), so the sum is negative. \(-25 + 9 = -16\).
    4. Same signs: \(4 + 19 = 23\). \(-4 + (-19) = -23\).
    5. \(50 – 31 = 19\), and \(50\) is larger, so the sum is positive. \(-31 + 50 = 19\).

    \(-21\), \(11\), \(-16\), \(-23\), \(19\)

    Problem 7: Subtracting Integers

    1. \(9 + (-14) = -5\)
    2. \(-6 + (-8) = -14\)
    3. \(5 + 7 = 12\)
    4. \(-10 + 4 = -6\)
    5. \(0 + 13 = 13\)

    Answers: \(-5\), \(-14\), 12, \(-6\), 13.

    Problem 8: More differences

    1. \(8 + (-15) = -7\)
    2. \(-12 + (-5) = -17\)
    3. \(7 + 9 = 16\)
    4. \(-14 + 14 = 0\)
    5. \(-20 + 35 = 15\)

    \(-7\), \(-17\), \(16\), \(0\), \(15\)

    Problem 9: Subtracting on a Number Line

    1. Subtracting \(9\) moves \(9\) units left: \(2 – 9 = -7\).
    2. Subtracting \(-5\) is adding \(5\): \(2 – (-5) = 7\).
    3. \(2 – 9 = 2 + (-9) = -7\).
    −10−9−8−7−6−5−4−3−2−1012345678910−9
    Part (a): \(2 – 9 = -7\).

    Answers: \(-7\), 7, \(2 + (-9)\).

    Problem 10: Three terms

    1. \(-8 + 15 = 7\). Then \(7 + (-12) = -5\).
    2. \(6 – (-4) = 6 + 4 = 10\). Then \(10 – 13 = -3\).
    3. \(-7 – (-9) = -7 + 9 = 2\). Then \(2 + (-3) = -1\).

    (a) \(-5\). (b) \(-3\). (c) \(-1\).

    Problem 11: Distance on a Number Line

    1. \(|-8 – 3| = |-11| = 11\) units.
    2. \(|-5 – (-12)| = |7| = 7\) units.
    3. \(|-4.5 – 2.5| = |-7| = 7\) units.
    4. \(|-8 – 3| = |-11| = 11\) and \(|3 – (-8)| = |11| = 11\), so they are equal.
    −10−9−8−7−6−5−4−3−2−101234567891011 unitsAB
    Distance \(AB = 11\).

    Answers: 11, 7, 7, and both expressions equal 11.

    Problem 12: Distances between points

    1. \(|-7 – (-2)| = |-5| = 5\) units.
    2. \(|-2 – 4.5| = |-6.5| = 6.5\) units.
    3. \(|-7 – 4.5| = |-11.5| = 11.5\) units. Check: \(5 + 6.5 = 11.5\).
    4. \(-7 – 3.5 = -10.5\).
    -8-7-6-5-4-3-2-101234565 units6.5 unitsPQR
    Distances along the number line add up.

    (a) 5 units. (b) 6.5 units. (c) 11.5 units. (d) \(-10.5\).

    Problem 13: Mixed number types

    1. \(-1.25 + 3.5 = 2.25\). Then \(2.25 – (-2.75) = 2.25 + 2.75 = 5\).
    2. Use sixths: \(-\frac{5}{6} – \frac{2}{6} = -\frac{7}{6}\). Then \(-\frac{7}{6} + \frac{3}{6} = -\frac{4}{6} = -\frac{2}{3}\).
    3. \(1\frac{1}{2} = \frac{3}{2} = \frac{9}{6}\) and \(-\frac{2}{3} = -\frac{4}{6}\). Distance: \(\frac{9}{6} – (-\frac{4}{6}) = \frac{13}{6} = 2\frac{1}{6}\).

    (a) \(5\). (b) \(-\frac{2}{3}\). (c) \(2\frac{1}{6}\).

    Problem 14: Fractions and Decimals

    1. \(-\frac{3}{4} + \frac{2}{4} = -\frac{1}{4}\). Then \(-\frac{1}{4} + \frac{5}{4} = \frac{4}{4} = 1\).
    2. \(-2.6 + 5.4 = 2.8\). Then \(2.8 + (-1.8) = 1\).
    3. \(\frac{3}{2} = 1.5\), so the distance is \(|-2.5 – 1.5| = |-4| = 4\).

    Answers: 1, 1, 4.

    Problem 15: Temperature Change

    1. \(-5 + 12 = 7\), so noon was \(7^{\circ}\text{F}\).
    2. \(7 – 9 = -2\), so 6 p.m. was \(-2^{\circ}\text{F}\).
    3. Change = final minus start: \(-11 – (-2) = -11 + 2 = -9\). The temperature changed by \(-9^{\circ}\text{F}\), a drop of \(9^{\circ}\text{F}\).
    −15010−56 a.m.7Noon−26 p.m.−11Midnight
    Temperatures through the day (\(^{\circ}\text{F}\)).

    Problem 16: Golf scores

    1. Highest: \(5\) (Diego). Lowest: \(-4\) (Priya). \(5 – (-4) = 5 + 4 = 9\).
    2. Ethan: \(3\). Aisha: \(-1\). \(3 – (-1) = 3 + 1 = 4\).
    3. \(-1 – 4 = -1 + (-4) = -5\).

    (a) 9 strokes. (b) 4 strokes. (c) \(-5\) (5 strokes under par).

    Problem 17: Yards gained and lost

    1. Gains are positive and losses are negative: \(7 + (-12) + 5 + (-9)\). \(7 + (-12) = -5\), then \(-5 + 5 = 0\), then \(0 + (-9) = -9\). The net yardage is \(-9\) yards.
    2. The team needs to go from \(-9\) to \(10\). \(10 – (-9) = 10 + 9 = 19\).

    Check: \(-9 + 19 = 10\).

    (a) \(-9\) yards (a net loss of 9 yards). (b) 19 yards.

    Problem 18: Elevation Differences

    1. \(35 – (-48) = 83\), so \(83\text{ ft}\).
    2. \(120 – (-48) = 168\), so \(168\text{ ft}\).
    3. \(-48 + 30 = -18\), so \(-18\text{ ft}\).
    4. \(35 – (-18) = 53\), so the diver is \(53\text{ ft}\) below the bird.
    −60−40−200204083 ftdiverbird
    Distance between diver and bird: 83 ft.

    Problem 19: Scuba dive

    1. Up \(12\): \(-35 + 12 = -23\). Down \(20\): \(-23 – 20 = -43\). Up \(15\): \(-43 + 15 = -28\).
    2. The final elevation is \(-28\text{ ft}\), which is \(28\text{ ft}\) below the surface.
    3. \(|-28 – (-35)| = |7| = 7\), so the distance is \(7\text{ ft}\).
    Surface 0 ft0-5-10-15-20-25-30-35-40-45Start -35 ftUp 12 -23 ftDown 20 -43 ftUp 15 -28 ft
    The four stops of the dive.

    (a) \(-23\text{ ft}\), \(-43\text{ ft}\), \(-28\text{ ft}\). (b) \(28\text{ ft}\). (c) \(7\text{ ft}\).

    Problem 20: Bank Balance

    1. After the check: \(45.50 – 72.25 = -26.75\). After the deposit: \(-26.75 + 30 = 3.25\). After the fee: \(3.25 – 5.75 = -2.50\). Balances: \(-\$26.75\), \(\$3.25\), \(-\$2.50\).
    2. Add the opposite of \(-2.50\): \(\$2.50\).
    −$30.00$0.00$50.00$45.50Start−$26.75Check$3.25Deposit−$2.50Fee
    Balance after each step.

    See every chapter on the Grade 7 math page.

    Voter... post

    More Grade 7 math

    Two-Step Inequalities

    Equations of Proportional Relationships

    Percent Problems: Tax, Tips, Markups and Discounts

    Equivalent Expressions

    Random Sampling and Making Inferences

    Comparing Two Populations