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Linear Functions: Slope-Intercept, Point-Slope and Standard Form: Algebra 1 Math Lesson – PDF Download

    Linear Functions: Slope-Intercept, Point-Slope and Standard Form – Algebra 1 math lesson

    This algebra 1 linear functions lesson explains linear functions: slope-intercept, point-slope and standard form in one printable page, with definitions, a method and a worked example.

    A linear function has a constant rate of change called its slope. It can be written as y = mx + b (slope-intercept), y – y1 = m(x – x1) (point-slope) or Ax + By = C (standard). Find the slope from two points, graph the line from any form, and write models from tables, graphs or words.

    Algebra 1Common Core: F-IF.C.7a · F-LE.A.1a · F-LE.A.2 · A-CED.A.2

    Algebra 1 Linear Functions Lesson: key facts

    • Standards F-IF.C.7a, F-LE.A.1a, F-LE.A.2 and A-CED.A.2: graph linear functions, recognize constant rates of change, and write linear models.
    • Slope from two points: \(m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\).
    • Slope-intercept \(y=mx+b\), point-slope \(y-y_{1}=m(x-x_{1})\), standard \(Ax+By=C\).
    • Parallel lines have equal slopes; perpendicular lines have slopes whose product is \(-1\).
    • In a model, the slope is the rate of change and the y-intercept is the starting value.

    What is slope and how do you find it?

    A linear function changes by the same amount every time \(x\) goes up by 1. That constant rate of change is the slope. Given two points \((x_{1},y_{1})\) and \((x_{2},y_{2})\), subtract the coordinates in the same order:

    \[m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\]

    For \((-2,1)\) and \((4,5)\), \(m=\frac{5-1}{4-(-2)}=\frac{4}{6}=\frac{2}{3}\). A positive slope rises from left to right, a negative slope falls, a horizontal line has slope 0, and a vertical line has undefined slope.

    −4−3−2−1123456−2−112345670xyA(−2, 1)B(4, 5)run = 6rise = 4
    Slope is rise over run: from \(A(-2,1)\) to \(B(4,5)\) the line rises 4 while it runs 6, so \(m=\frac{4}{6}=\frac{2}{3}\).

    What are the three forms of a linear equation?

    Forms of a line

    Slope-intercept form: \(y=mx+b\), where \(m\) is the slope and \(b\) is the y-intercept.

    Point-slope form: \(y-y_{1}=m(x-x_{1})\), for a line with slope \(m\) through \((x_{1},y_{1})\).

    Standard form: \(Ax+By=C\), usually with integer coefficients and \(A\ge 0\).

    Slope-intercepty = mx + bPoint-slopey − y₁ = m(x − x₁)StandardAx + By = C
    The three forms describe the same line; each one makes a different feature easy to see.

    To convert, solve for \(y\) or clear fractions. For example, \(2x+3y=12\) becomes \(3y=-2x+12\), so \(y=-\frac{2}{3}x+4\).

    How do you graph a line from its equation?

    1. Write the equation in a form that shows a point and the slope.
    2. Plot that point, such as the y-intercept \((0,b)\).
    3. Use rise over run to plot at least one more point, then draw the line through them.
    4. Check a third point in the equation.

    Worked example. Graph \(y=-\frac{2}{3}x+4\). Plot \((0,4)\). The slope \(-\frac{2}{3}\) means down 2 and right 3, which gives \((3,2)\) and \((6,0)\). Check: \(-\frac{2}{3}(6)+4=0\).

    −2−112345678−2−11234560xy(0, 4)(3, 2)(6, 0)run 3rise −2
    Graphing \(y=-\frac{2}{3}x+4\): plot the y-intercept \((0,4)\), then go right 3 and down 2 to reach \((3,2)\) and again to reach \((6,0)\).

    How are parallel and perpendicular lines related?

    Parallel lines have equal slopes and different y-intercepts. Perpendicular lines have slopes that are negative reciprocals, so their product is \(-1\). If \(m=2\), a perpendicular line has slope \(-\frac{1}{2}\).

    −4−3−2−1123456−6−5−4−3−2−11234560xyy = 2x + 1y = 2x − 3y = −½x + 1
    The two blue and green lines share slope 2, so they are parallel. The orange line has slope \(-\frac{1}{2}\), the negative reciprocal of 2, so it is perpendicular to both.

    How do you write a linear model from a situation?

    Find the constant rate of change (the slope) and the starting value (the y-intercept). A gym that charges a \(\$25\) sign-up fee plus \(\$18\) per month has cost \(C=18m+25\). Two points from a table also work: find \(m\) first, then use point-slope form.

    Linear Functions: Slope-Intercept, Point-Slope and Standard Form: frequently asked questions

    How do you find the slope of a line from two points?

    Divide the change in y by the change in x, keeping the same point first in both differences. For \((1,3)\) and \((5,11)\), \(m=\frac{11-3}{5-1}=2\).

    Which form of a linear equation should I use?

    Use slope-intercept form to graph quickly from the y-intercept and slope. Use point-slope form when you know a point and the slope. Use standard form to find intercepts or to write equations with integer coefficients.

    How do you convert standard form to slope-intercept form?

    Solve the equation for \(y\). For \(3x+4y=12\), subtract \(3x\) to get \(4y=-3x+12\), then divide by 4 to get \(y=-\frac{3}{4}x+3\).

    How do you write a line parallel or perpendicular to a given line?

    A parallel line keeps the same slope. A perpendicular line uses the negative reciprocal of the slope. Then plug the given point into point-slope form.

    What do slope and y-intercept mean in a word problem?

    The slope is the amount the output changes per one unit of input, such as dollars per month. The y-intercept is the starting amount when the input is 0, such as a sign-up fee.

    How to use this algebra 1 linear functions lesson

    Use this algebra 1 linear functions lesson before the worksheet, then check what you learned with the quiz.

    Next step after this algebra 1 linear functions lesson: Linear Functions: Slope-Intercept, Point-Slope and Standard Form worksheet

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