Mathovore, everything you need to succeed in math: Common Core lessons, worksheets, tests and quizzes
Skip to content

Logic and Two-Column Proofs: Geometry Math Worksheet Answer Key – PDF Download

    Logic and Two-Column Proofs – Geometry math worksheet answer key

    Each solution names the statement, the reason or the counterexample. For proofs, check that every reason is Given, a definition, a postulate, a property or a theorem, and that the last statement is the Prove.

    GeometryCommon Core: G-CO.C.9

    Problem 1: Hypothesis and conclusion

    Hypothesis (after if): it rains on Saturday. Conclusion (after then): the Little League game is canceled.

    Problem 2: Writing if-then form

    If a number is divisible by both 2 and 3, then it is divisible by 6. The hypothesis is “a number is divisible by both 2 and 3.” The words after if in the original sentence form the hypothesis.

    Problem 3: Rewriting a statement

    If a figure is a square, then it has four congruent sides.

    Problem 4: Writing a converse

    Converse: If a figure is a rectangle, then it is a square. It is false.

    Counterexample: a rectangle that measures 5 cm by 3 cm has four right angles but its sides are not equal.

    5 cm3 cm
    A 5 cm by 3 cm rectangle is not a square.

    Problem 5: Inverse and contrapositive

    Inverse (negate both parts): If an angle does not measure \(90^{\circ}\), then it is not a right angle.

    Contrapositive (swap and negate): If an angle is not a right angle, then it does not measure \(90^{\circ}\).

    Problem 6: Truth values of related statements

    1. Statement: true (every multiple of 4 is even).
    2. Converse: “If a number is even, then it is a multiple of 4.” False; counterexample 6.
    3. Inverse: “If a number is not a multiple of 4, then it is not even.” False; counterexample 6.
    4. Contrapositive: “If a number is not even, then it is not a multiple of 4.” True, matching the statement.

    Problem 7: Counterexample with primes

    The number 2 is prime, because its only factors are 1 and 2, but it is even. The hypothesis is true and the conclusion is false, so the statement is false.

    Problem 8: Counterexample with squares

    Let \(x=-7\). Then \((-7)^{2}=49\), so the hypothesis is true, but \(x\neq 7\). \(x=-7\) is a counterexample.

    Problem 9: Counterexample with angles

    \(100+80=180\), so the angles are supplementary and the hypothesis is true. They do not share a side, so they are not a linear pair and the conclusion is false.

    The two angles in the figure are a counterexample.

    100°80°
    Supplementary angles that do not form a linear pair.

    Problem 10: Inductive pattern of dots

    Counts: 2, 6, 12, 20. The differences are 4, 6, 8, so the next differences are 10 and 12.

    Pattern 5: \(20+10=30\). Pattern 6: \(30+12=42\).

    Pattern n is a rectangle with n rows and n + 1 columns: \(n(n+1)\). Check: \(5\times 6=30\) and \(6\times 7=42\).

    Problem 11: Inductive or deductive?

    1. Inductive: it generalizes from a pattern of cases.
    2. Deductive: it applies a general fact to a specific case.
    3. Inductive: three measured cases suggest a rule but do not prove it.
    4. Deductive: it applies a known theorem to a specific triangle.

    Problem 12: Making a conjecture

    Every sum is even. Conjecture: the sum of two odd numbers is even. This is inductive reasoning, so it is a conjecture until it is proven.

    Problem 13: Disproving a conjecture

    Try a negative number: \(-3+5=2\) and \(2 < 5\). The sum 2 is not greater than 5. The numbers \(-3\) and 5 are a counterexample.

    Problem 14: Naming properties of equality

    1. Symmetric Property.
    2. Transitive Property.
    3. Reflexive Property.
    4. Division Property of Equality (divide both sides by 3).

    Problem 15: Supplying reasons

    Statements Reasons
    1. \(3x+7=22\) 1. Given
    2. \(3x=15\) 2. Subtraction Property of Equality (subtract 7 from both sides)
    3. \(x=5\) 3. Division Property of Equality (divide both sides by 3)

    Check: \(3(5)+7=22\).

    Problem 16: Supplying statements

    Statements Reasons
    1. \(\angle 1\) and \(\angle 2\) are complementary; \(m\angle 1=35^{\circ}\) 1. Given
    2. \(m\angle 1+m\angle 2=90^{\circ}\) 2. Definition of complementary angles
    3. \(35^{\circ}+m\angle 2=90^{\circ}\) 3. Substitution Property of Equality
    4. \(m\angle 2=55^{\circ}\) 4. Subtraction Property of Equality

    Check: \(35+55=90\).

    Problem 17: Midpoint proof

    Statements Reasons
    1. M is the midpoint of \(\overline{ST}\); \(ST=24\) 1. Given
    2. \(SM=MT\) 2. Definition of midpoint
    3. \(SM+MT=ST\) 3. Segment Addition Postulate
    4. \(SM+SM=24\) 4. Substitution Property of Equality
    5. \(2(SM)=24\) 5. Combining like terms
    6. \(SM=12\) 6. Division Property of Equality

    Problem 18: Vertical angles proof

    Statements Reasons
    1. Lines ℓ and m intersect 1. Given
    2. \(\angle 2\) and \(\angle 3\) are a linear pair; \(\angle 3\) and \(\angle 4\) are a linear pair 2. Definition of linear pair
    3. \(\angle 2\) and \(\angle 3\) are supplementary; \(\angle 3\) and \(\angle 4\) are supplementary 3. Linear Pair Postulate
    4. \(m\angle 2+m\angle 3=180^{\circ}\); \(m\angle 3+m\angle 4=180^{\circ}\) 4. Definition of supplementary angles
    5. \(m\angle 2+m\angle 3=m\angle 3+m\angle 4\) 5. Transitive Property of Equality (both sums equal 180)
    6. \(m\angle 2=m\angle 4\) 6. Subtraction Property of Equality (subtract \(m\angle 3\))
    7. \(\angle 2\) ≅ \(\angle 4\) 7. Definition of congruent angles
    68°112°68°112°ℓm
    Example: angles 2 and 4 both measure 112°.

    Problem 19: Paragraph proof

    Because \(\angle A\) and \(\angle B\) are complementary, \(m\angle A+m\angle B=90^{\circ}\). Because \(\angle C\) and \(\angle B\) are complementary, \(m\angle C+m\angle B=90^{\circ}\). Both sums equal \(90^{\circ}\), so \(m\angle A+m\angle B=m\angle C+m\angle B\) by the Transitive Property of Equality. Subtracting \(m\angle B\) from both sides gives \(m\angle A=m\angle C\). Angles with equal measures are congruent, so \(\angle A\) ≅ \(\angle C\).

    Problem 20: Contrapositive in context

    Contrapositive: “If a student does not have a GPA of at least 3.5, then the student is not on the honor roll.” Since \(3.2 < 3.5\), Priya’s GPA is below 3.5.

    Priya is not on the honor roll. The contrapositive is true because the original rule is true.

    Problem 21: Chaining conditionals

    Link the conclusion of the first rule to the hypothesis of the second: If it snows more than 6 inches, then the bake sale moves to Sunday.

    Eight inches is more than 6 inches, so the hypothesis is true. Therefore the bake sale moves to Sunday.

    Problem 22: Solve and justify

    1. \(3x+14=5x-6\): Vertical Angles Theorem (\(\angle 1\) ≅ \(\angle 3\)).

    2. \(20=2x\): Addition and Subtraction Properties of Equality. 3. \(x=10\): Division Property of Equality.

    4. \(m\angle 1\)\(=3(10)+14=44^{\circ}\): Substitution. 5. \(\angle 1\) and \(\angle 2\) are a linear pair, so they are supplementary: \(m\angle 2\)\(=180-44=136^{\circ}\). 136°.

    44°136°44°136°ℓm
    Check: 44° + 136° = 180°.

    Problem 23: Writing a biconditional

    Converse: If the measure of an angle is \(90^{\circ}\), then it is a right angle. It is true by the definition of a right angle.

    Biconditional: An angle is a right angle if and only if its measure is \(90^{\circ}\).

    See every chapter on the Geometry math page.

    Voter... post

    More Geometry math

    Parallel Lines, Transversals and Proofs

    Parallelograms and Special Quadrilaterals

    Circles: Chords, Arcs and Inscribed Angles

    Arc Length, Sector Area and Radians

    Area and Volume Formulas

    Cross Sections, Solids of Rotation and Geometric Modeling