Grade 5 Divide Worksheet Answer Key – Free PDF

Contents

This grade 5 divide worksheet answer key solves all 23 problems of the dividing whole numbers worksheet step by step.

Each solution shows partial quotients and subtraction steps, then a check by multiplication. The final answer is in bold. If your quotient is different, recheck each subtraction and the place value of each partial quotient.

Grade 5Common Core: 5.NBT.B.6

Grade 5 Divide Worksheet Answer Key: problems 1–5

Problem 1: Area model warm-up

$6 \times 100 = 600$, and $756 – 600 = 156$.
$6 \times 20 = 120$, and $156 – 120 = 36$.
$6 \times 6 = 36$, and $36 – 36 = 0$.

Check: $6 imes 126 = 756$.

126

Filled area model.

Problem 2: Two-digit divisor

$15 \times 60 = 900$, and $960 – 900 = 60$.
$15 \times 4 = 60$, and $60 – 60 = 0$.

Check: $15 imes 64 = 960$.

Problem 3: One-digit divisor

$4 \times 300 = 1{,}200$, and $1{,}248 – 1{,}200 = 48$.
$4 \times 10 = 40$, and $48 – 40 = 8$.
$4 \times 2 = 8$, and $8 – 8 = 0$.

Check: $4 imes 312 = 1{,}248$.

312

Problem 4: Place-value pattern

4,200 is 420 tens and 60 is 6 tens. $420 : 6 = 70$.

Check: $60 \times 70 = 4{,}200$.

Problem 5: Exact division

$24 \times 30 = 720$, and $744 – 720 = 24$.
$24 \times 1 = 24$, and $24 – 24 = 0$.

Check: $24 imes 31 = 744$.

Grade 5 Divide Worksheet Answer Key: problems 6–10

Problem 6: A remainder

$7 \times 100 = 700$, and $905 – 700 = 205$.
$7 \times 20 = 140$, and $205 – 140 = 65$.
$7 \times 9 = 63$, and $65 – 63 = 2$.

Check: $7 imes 129 = 903$, and $903 + 2 = 905$.

129 R 2

Problem 7: Four digits, two-digit divisor

$35 \times 60 = 2{,}100$, and $2{,}415 – 2{,}100 = 315$.
$35 \times 9 = 315$, and $315 – 315 = 0$.

Check: $35 imes 69 = 2{,}415$.

The same work as long division.

Problem 8: Partial quotients

$21 \times 70 = 1{,}470$, and $1{,}596 – 1{,}470 = 126$.
$21 \times 6 = 126$, and $126 – 126 = 0$.

Check: $21 imes 76 = 1{,}596$.

Problem 9: Divide 3,078 by 18

$18 \times 100 = 1{,}800$, and $3{,}078 – 1{,}800 = 1{,}278$.
$18 \times 70 = 1{,}260$, and $1{,}278 – 1{,}260 = 18$.
$18 \times 1 = 18$, and $18 – 18 = 0$.

Check: $18 imes 171 = 3{,}078$.

171

Problem 10: A zero in the quotient

$42 \times 100 = 4{,}200$, and $4{,}284 – 4{,}200 = 84$.
$42 \times 2 = 84$, and $84 – 84 = 0$.

Check: $42 imes 102 = 4{,}284$.

102

The zero in the quotient holds the tens place.

Grade 5 Divide Worksheet Answer Key: problems 11–15

Problem 11: Divide 5,238 by 54

$54 \times 90 = 4{,}860$, and $5{,}238 – 4{,}860 = 378$.
$54 \times 7 = 378$, and $378 – 378 = 0$.

Check: $54 imes 97 = 5{,}238$.

Problem 12: Divide with zeros

$25 \times 200 = 5{,}000$, and $6{,}500 – 5{,}000 = 1{,}500$.
$25 \times 60 = 1{,}500$, and $1{,}500 – 1{,}500 = 0$.

Check: $25 imes 260 = 6{,}500$.

260

Problem 13: Estimate with compatible numbers

4,187 is close to 4,000 and 52 is close to 50. Estimate: $4{,}000 : 50 = 80$.

$52 \times 80 = 4{,}160$, and $4{,}187 – 4{,}160 = 27$.

Check: $52 imes 80 = 4{,}160$, and $4{,}160 + 27 = 4{,}187$.

80 R 27

The exact answer is close to the estimate, so it is reasonable.

4,187 is near 4,200 and 4,000; 4,000 is the compatible number used.

Problem 14: A remainder with two digits

$31 \times 60 = 1{,}860$, and $2{,}009 – 1{,}860 = 149$.
$31 \times 4 = 124$, and $149 – 124 = 25$.

Check: $31 imes 64 = 1{,}984$, and $1{,}984 + 25 = 2{,}009$.

64 R 25

Problem 15: Check with multiplication

Check: $43 \times 183 = 7{,}869$. That is not 7,863, so Diego is wrong.

$43 \times 100 = 4{,}300$, and $7{,}863 – 4{,}300 = 3{,}563$.
$43 \times 80 = 3{,}440$, and $3{,}563 – 3{,}440 = 123$.
$43 \times 2 = 86$, and $123 – 86 = 37$.

Check: $43 imes 182 = 7{,}826$, and $7{,}826 + 37 = 7{,}863$.

182 R 37

Grade 5 Divide Worksheet Answer Key: problems 16–20

Problem 16: Fill the division area model

$24 \times 100 = 2{,}400$, and $3{,}696 – 2{,}400 = 1{,}296$.
$24 \times 50 = 1{,}200$, and $1{,}296 – 1{,}200 = 96$.
$24 \times 4 = 96$, and $96 – 96 = 0$.

Check: $24 imes 154 = 3{,}696$.

154

Completed area model.

Problem 17: Find the mistake

Check: $15 \times 21 = 315$, not 3,150. Ana left out a zero: 15 does not go into 31 twice, 3,150 is 315 tens, and $315 : 15 = 21$ tens.

$15 \times 200 = 3{,}000$ and $15 \times 10 = 150$, so $3{,}150 : 15 = 210$.

Ana dropped the zero (the ones digit); the quotient is 210.

Problem 18: Cookie boxes

$12 \times 20 = 240$, and $288 – 240 = 48$.
$12 \times 4 = 48$, and $48 – 48 = 0$.

Check: $12 imes 24 = 288$.

24 boxes.

Problem 19: Buses for a field trip

$46 \times 20 = 920$, and $1{,}100 – 920 = 180$.
$46 \times 3 = 138$, and $180 – 138 = 42$.

Check: $46 imes 23 = 1{,}058$, and $1{,}058 + 42 = 1{,}100$.

The 42 students left over still need a bus, so one more bus is needed: 23 + 1 = 24.

24 buses.

Problem 20: Bags of apples

Step 1: bags.

$15 \times 100 = 1{,}500$, and $2{,}550 – 1{,}500 = 1{,}050$.
$15 \times 70 = 1{,}050$, and $1{,}050 – 1{,}050 = 0$.

Check: $15 imes 170 = 2{,}550$.

Step 2: $170 \times 4 = 680$.

$680.

Grade 5 Divide Worksheet Answer Key: problems 21–23

Problem 21: Road trip speed

$21 \times 60 = 1{,}260$, and $1{,}365 – 1{,}260 = 105$.
$21 \times 5 = 105$, and $105 – 105 = 0$.

Check: $21 imes 65 = 1{,}365$.

65 miles per hour.

Problem 22: Baseballs for teams

Step 1: cases.

$24 \times 60 = 1{,}440$, and $1{,}440 – 1{,}440 = 0$.

Check: $24 imes 60 = 1{,}440$.

Step 2: $60 : 15 = 4$.

4 cases.

Problem 23: Bead bracelets

$36 \times 50 = 1{,}800$, and $1{,}874 – 1{,}800 = 74$.
$36 \times 2 = 72$, and $74 – 72 = 2$.

Check: $36 imes 52 = 1{,}872$, and $1{,}872 + 2 = 1{,}874$.

52 bracelets with 2 beads left over.

How to use this grade 5 divide worksheet answer key

Read this grade 5 divide worksheet answer key after trying each problem yourself, and redo any problem you missed.

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Grade 5 Dividing Whole Numbers worksheet answer key

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