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Pascal’s Triangle

Key takeaway: Pascal’s triangle is a triangular array where each entry is the sum of the two entries above it, and row n lists the binomial coefficients C(n, 0) through C(n, n).

Grade 12 – PrecalculusA-APR.C.5Expressions and Equations

Definition of Pascal's Triangle

Definition

Pascal’s triangle starts with a single 1 at the top. Every new row begins and ends with 1, and each number inside is the sum of the two numbers diagonally above it. Rows are counted from row 0 at the top.

Beneath this simple rule hides a lot of mathematics. Row \(n\) holds the coefficients of \((a+b)^n\), the numbers of ways to choose \(k\) items from \(n\), and sums that double from one row to the next. Diagonals contain the counting numbers, the triangular numbers and more. The array was known in several cultures long before it carried Blaise Pascal’s name.

Formula and notation

The entry in row \(n\), position \(k\) (both counted from 0) is

\[\binom\,{n}{k}=\binom\,{n-1}{k-1}+\binom\,{n-1}{k},\qquad \sum_{k=0}^{n}\binom\,{n}{k}=2^{n}.\]

The first formula is the “add the two above” rule; the second says that row \(n\) sums to \(2^n\).

111121133114641151010511615201561row 5row 6: 10 + 10 = 20
Each inner entry is the sum of its two neighbors in the row above.

Key facts

  • Each row is a mirror image of itself, because C(n, k) = C(n, n − k).
  • Row 5 is 1, 5, 10, 10, 5, 1, and its entries add to 32.
  • Row n has n + 1 entries, numbered from position 0 to position n.
  • Reading row n gives the coefficients for expanding a binomial to the power n.

Pascal's Triangle example

Problem

Build row 7 of the triangle from row 6, then find the sum of row 7 and the value of \(\binom\,{7}{3}\).

  1. Row 6 is 1, 6, 15, 20, 15, 6, 1.

  2. Add neighbors: \(6+1=7\), \(15+6=21\), \(20+15=35\), and by symmetry \(35, 21, 7\). Row 7: 1, 7, 21, 35, 35, 21, 7, 1.

  3. Row sum: \(2^7=128\); check \(1+7+21+35+35+21+7+1=128\).

  4. Position 3 of row 7 is 35.

Row 7 adds to 128, and \(\binom\,{7}{3}=\)35.

Common mistake

Watch out

Cyrus wants \(\binom\,{7}{3}\) and reads the third number of row 7, which is 21.

Why it is wrong

Positions are counted from 0, and rows too. The entry \(\binom\,{7}{3}\) is the fourth number: 1, 7, 21, 35. Counting from 1 is the usual slip in Pascal’s triangle.

Related terms and lessons

Browse the glossary: A–Z list · Precalculus vocabulary · Expressions and Equations

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