Mathovore, everything you need to succeed in math: Common Core lessons, worksheets, tests and quizzes
Skip to content

Euler’s Number (e)

Euler's Number (e) – definition and example, Algebra 2 math glossary – Mathovore

Key takeaway: Euler’s number is the irrational constant e ≈ 2.71828, the value approached by (1 + 1/n)^n as n grows without bound and the natural base for continuous growth and decay.

Grade 11 – Algebra 2F-LE.A.4Functions and Graphs

Definition of Euler's Number

Definition

Euler’s number, written \(e\), is a constant a little larger than 2.7. It appears when growth happens continuously instead of in jumps. Imagine a balance that earns 100% interest per year. Paying the interest in more and more installments helps, but the balance never passes a ceiling of about 2.71828 times the start.

That ceiling is \(e\). Like \(\pi\), it is irrational: its decimal expansion never ends and never repeats. It is the base of the natural exponential function \(e^x\), which grows at a speed equal to its own value.

Formula and notation

Euler’s number is defined by a limit:

\[e=\lim_{n\to\infty}(1+\frac{1}{n})^{n}\approx 2.71828.\]

For continuous growth or decay, the amount after time \(t\) is \(A=Pe^{rt}\), where \(P\) is the start and \(r\) the rate per unit of time as a decimal.

e ≈ 2.718282.0002.2502.4412.6132.7052.717n = 1n = 2n = 4n = 12n = 100n = 1000
Bars show (1 + 1/n)^n (axis starts at 1.5); they creep up toward e.

Key facts

  • Euler’s number starts 2.718281828, but its digits never settle into a repeating pattern.
  • The function e^x equals its own rate of change at every point.
  • The inverse of e^x is the natural logarithm ln x.
  • Continuous compounding always earns slightly more than any fixed number of payments per year.

Euler's Number example

Problem

Mateo invests \$2,400 at 3.5% annual interest compounded continuously. How much is in the account after 8 years?

  1. Use \(A=Pe^{rt}\) with \(P=2400\), \(r=0.035\), \(t=8\).

  2. The exponent is \(rt=0.035\times 8=0.28\).

  3. Compute \(e^{0.28}\approx 1.32313\), then \(2400\times 1.32313\approx 3175.51\).

The balance is about \$3,175.51.

Common mistake

Watch out

Hana argues that as \(n\) gets huge, \(\frac{1}{n}\) goes to 0, so \((1+\frac{1}{n})^n\) becomes \(1^n=1\).

Why it is wrong

Two things happen at once: the base shrinks toward 1 while the exponent grows without limit. Their tug of war ends at 2.71828, not 1. At \(n=1000\) the value is already 2.717.

Related terms and lessons

Browse the glossary: A–Z list · Algebra 2 vocabulary · Functions and Graphs

Rate this page