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Pythagorean Identity

Pythagorean Identity – definition and example, Algebra 2 math glossary – Mathovore

Key takeaway: The Pythagorean identity states that sin²θ + cos²θ = 1 for every angle θ, which lets you find one of sine or cosine from the other up to a sign.

Grade 11 – Algebra 2F-TF.C.8Trigonometry

Definition of Pythagorean Identity

Definition

The Pythagorean identity says that the square of the sine plus the square of the cosine of any angle is exactly 1. It is the Pythagorean theorem wearing trig clothing.

On a circle of radius 1, the point at angle \(\theta\) is \((\cos\theta,\sin\theta)\). Its horizontal and vertical distances from the center are the legs of a right triangle, and the radius is the hypotenuse. Squaring and adding the legs must give \(1^2\). Because the statement is true for all angles, it is called an identity rather than an equation to solve.

Formula and notation

The identity and two rearrangements:

\[\sin^2\theta+\cos^2\theta=1,\quad \sin\theta=\pm\sqrt{1-\cos^2\theta},\quad \cos\theta=\pm\sqrt{1-\sin^2\theta}.\]

The notation \(\sin^2\theta\) means \((\sin\theta)^2\). The \(\pm\) is settled by the quadrant.

|cos| = 15/17sin = 8/171(8/17)² + (15/17)²= 64/289 + 225/289= 289/289 = 1
The legs 8/17 and 15/17 and the radius 1 satisfy the Pythagorean theorem.

Key facts

  • It holds in radians and degrees, for positive, negative and large angles.
  • Dividing every term by cos²θ gives the companion identity 1 + tan²θ = sec²θ.
  • Neither sine nor cosine can exceed 1 in size, a direct consequence.
  • The quadrant of θ decides which sign to keep after a square root.

Pythagorean Identity example

Problem

An angle \(\theta\) in quadrant II has \(\sin\theta=\frac{8}{17}\). Find \(\cos\theta\) and \(\tan\theta\).

  1. Rearrange the identity and square: 1 minus \(\frac{64}{289}\) leaves \(\frac{225}{289}\) for the squared cosine.

  2. The root of that fraction is 15 over 17, with a possible minus sign.

  3. Quadrant II has negative cosine, so \(\cos\theta=-\frac{15}{17}\).

  4. Divide sine by cosine: \(\tan\theta=-\frac{8}{15}\).

\(\cos\theta=\)\(-\frac{15}{17}\) and \(\tan\theta=-\frac{8}{15}\).

Common mistake

Watch out

Marcus recalls the Pythagorean identity as \(\sin\theta+\cos\theta=1\). With \(\sin\theta=\frac{8}{17}\) he gets \(\cos\theta=\frac{9}{17}\).

Why it is wrong

The squares matter. Without them the statement is false: at 45° the sum of sine and cosine is about 1.41. Square first, subtract from 1, take a root and pick the sign by quadrant.

Related terms and lessons

Browse the glossary: A–Z list · Algebra 2 vocabulary · Trigonometry

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