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Elimination Method

Elimination Method – definition and example, Grade 8 math glossary – Mathovore

Key takeaway: The elimination method makes one unknown disappear by combining two equations, adding or subtracting them, so only one unknown is left to solve for.

Grade 88.EE.C.8bExpressions and Equations

Definition of Elimination Method

Definition

The elimination method exploits a simple fact: adding equal things to equal things keeps the balance. Stack two equations, add or subtract them, and if the coefficients of one unknown are opposites or equal, that unknown vanishes.

Look at the y-terms in \(3x + 2y = 17\) and \(5x – 2y = 7\). They are \(+2y\) and \(-2y\), so adding the equations makes them cancel. When no pair cancels, multiply one or both equations by a number first to create matching coefficients. The method shines when both equations are written in the same \(Ax + By = C\) pattern, and it avoids fractions that substitution can produce.

Formula and notation

Line up like terms, then combine the left sides and the right sides together:

\[(3x + 2y) + (5x – 2y) = 17 + 7 \ \Rightarrow\ 8x = 24\]

Opposite coefficients: add. Equal coefficients: subtract.

3x+ 2y= 175x– 2y= 78x= 24+2y and -2y cancelx = 3, then y = 4: solution (3, 4)
Opposite y-terms vanish when the two equations are added.

Key facts

  • The elimination method adds the equations when coefficients of one unknown are opposites.
  • Subtract the equations when the coefficients are exactly equal.
  • If nothing matches, multiply a whole equation to create a match.
  • After finding one variable, substitute to get the other and check.

Elimination Method example

Problem

Use the elimination method on \(3x + 2y = 17\) and \(5x – 2y = 7\).

  1. The y-terms are \(+2y\) and \(-2y\), opposites, so add: \(8x = 24\) and \(x = 3\).

  2. Substitute into the first equation: \(3(3) + 2y = 17\), so \(2y = 8\) and \(y = 4\).

  3. Check in the second: \(5(3) – 2(4) = 15 – 8 = 7\). It works.

The solution is \((3, 4)\).

Common mistake

Watch out

For \(4x + 3y = 18\) and \(2x + 3y = 12\), Beck adds the equations and gets \(6x + 6y = 30\), which still has two unknowns.

Why it is wrong

The y-coefficients are equal, not opposite, so adding keeps them. Subtract instead: \((4x – 2x) + (3y – 3y) = 18 – 12\), giving \(2x = 6\) and \(x = 3\). Then \(12 + 3y = 18\) gives \(y = 2\). Remember to subtract every term, including the right-hand sides.

Related terms and lessons

Browse the glossary: A–Z list · Grade 8 vocabulary · Expressions and Equations

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