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Integral

Integral – definition and example, AP Calculus AB math glossary – Mathovore

Key takeaway: An integral adds up a continuously changing quantity: the indefinite form gives the family of antiderivatives, and the definite form gives the net accumulated amount, or signed area, over an interval.

Grade 12 – AP Calculus ABAP Calculus AB Unit 6Calculus

Definition of Integral

Definition

An integral is the calculus tool for accumulating. If a faucet’s flow rate changes every second, the integral of the rate adds up all the tiny amounts to give the total water. On a graph, that total is the signed area between the curve and the horizontal axis.

There are two forms. One with no limits returns a function plus a constant. One with limits of integration returns a single number. Differentiation and integration are inverse processes.

Formula and notation

Indefinite and definite forms:

\[ \int h(x)\,dx=H(x)+C,\qquad \int_{m}^{n} h(x)\,dx=H(n)-H(m). \]

The symbol \(\int\) is a stretched S for sum, \(h(x)\) is the integrand, and \(dx\) names the variable. Here \(H^{\prime}=h\).

3x^2x^3 + Cintegratedifferentiateinverse operations
Integrating and differentiating undo each other, up to the constant C.

Key facts

  • Area above the axis counts as positive and area below it as negative.
  • The differential dx is not decoration; it names the variable of integration.
  • Sums and constant multiples pass through the integral sign.
  • Check an indefinite result by differentiating; you must get the integrand back.

Integral example

Problem

Evaluate the indefinite integral \(\int(10x^4-6x+3e^x)dx\).

  1. Split by sums: integrate each term separately.

  2. Powers: \(\int 10x^4\,dx=2x^5\) and \(\int 6x\,dx=3x^2\). Exponential: \(\int 3e^x\,dx=3e^x\).

  3. Combine, keeping the sign on the middle term, and add one constant.

The integral is \(2x^5-3x^2+3e^x+C\).

Common mistake

Watch out

A student computes \(\int x\cdot x\,dx\) as \(\frac{x^2}{2}\cdot\frac{x^2}{2}=\frac{x^4}{4}\), integrating each factor separately.

Why it is wrong

This operation does not split over products. Rewrite \(x\cdot x=x^2\), then \(\int x^2\,dx=\frac{x^3}{3}+C\). Differentiating the student’s \(\frac{x^4}{4}\) gives \(x^3\), not \(x^2\), which exposes the error.

Related terms and lessons

Browse the glossary: A–Z list · AP Calculus AB vocabulary · Calculus

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