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Synthetic Division

Synthetic Division – definition and example, Algebra 2 math glossary – Mathovore

Key takeaway: Synthetic division is a compact table method for dividing by x − r that uses only the coefficients and the number r to produce the quotient and a remainder.

Grade 11 – Algebra 2A-APR.D.6Expressions and Equations

Definition of Synthetic Division

Definition

Synthetic division boils polynomial division down to arithmetic on coefficients. It applies only when the divisor looks like \(x – 4\) or \(x + 2\): first power of \(x\), with a coefficient of exactly 1.

You write the zero of the divisor on the left, the coefficients of the dividend in a row, bring down the first coefficient, then repeatedly multiply by the zero and add. The last number is the remainder, and the others are the coefficients of the quotient, one degree lower than the dividend. The remainder equals the value of the polynomial at the zero.

Formula and notation

For synthetic division by \(x – r\), put \(r\) in the box; for divisor \(x + 2\), that means \(r = -2\):

\[ P(x) = (x – r)\,Q(x) + R, \qquad R = P(r) \]

Fill any missing power of \(x\) with a coefficient of 0 before starting.

-234-17-6-64263-2-1320quotient: 3x² – 2x – 13remainder: 20 = P(-2)multiply by -2add down
Multiply each bottom number by -2, write it under the next coefficient, and add.

Key facts

  • The number in the box is the zero of the divisor, so x + 2 uses -2.
  • Bring down, multiply, add, and repeat across the row.
  • The last number is the remainder and equals P(r).
  • A remainder of 0 shows that x – r is a factor of the polynomial.

Synthetic Division example

Problem

Divide \(3x^3 + 4x^2 – 17x – 6\) by \(x + 2\) using synthetic division.

  1. Divisor \(x + 2\) means \(r = -2\). Coefficients: 3, 4, \(-17\), \(-6\). Bring down 3.

  2. \(3 \times (-2) = -6\); \(4 + (-6) = -2\). Then \(-2 \times (-2) = 4\); \(-17 + 4 = -13\).

  3. \(-13 \times (-2) = 26\); \(-6 + 26 = 20\). The last number is the remainder.

The quotient is \(3x^2 – 2x – 13\) with remainder 20, so the result is \(3x^2 – 2x – 13 + \frac{20}{x+2}\).

Common mistake

Watch out

Cora divides by \(x + 2\) using \(r = 2\) in the box and obtains a remainder of 4.

Why it is wrong

The box holds the zero of the divisor, the value that makes it 0. For \(x + 2\) that is \(-2\), not 2. With \(r = 2\) she is really dividing by \(x – 2\). Check with the remainder theorem: \(P(-2) = 3(-8) + 4(4) – 17(-2) – 6 = 20\).

Related terms and lessons

Browse the glossary: A–Z list · Algebra 2 vocabulary · Expressions and Equations

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