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Complex Number

Complex Number – definition and example, Algebra 2 math glossary – Mathovore

Key takeaway: A complex number pairs an ordinary number with a multiple of i, written p + qi, so it has a horizontal real part p and a vertical imaginary part q on the complex plane.

Grade 11 – Algebra 2N-CN.A.1Numbers and Operations

Definition of Complex Number

Definition

Each complex number carries two pieces of information. In \(p + qi\), the piece \(p\) is the real part, and \(q\), the multiplier of \(i\), is the imaginary part. A plain 8 is complex with \(q = 0\), and a number like \(5i\) is complex with \(p = 0\).

Addition and subtraction combine like pieces. Multiplication works like expanding two binomials, plus the extra rule \(i^2 = -1\). Each number can be drawn as a point: real part along the horizontal axis, imaginary part up the vertical axis.

Formula and notation

A complex number in standard form, and a sum of two of them (real parts \(p, r\), imaginary parts \(q, s\)):

\[ z = p + qi, \qquad (p + qi) + (r + si) = (p + r) + (q + s)i \]

The product uses distribution and \(i^2 = -1\): \((p+qi)(r+si) = (pr – qs) + (ps + qr)i\).

3 + 5i-7 + 2i-4 + 7irealimaginary(3 + 5i) + (-7 + 2i)= -4 + 7i
Adding complex numbers adds the horizontal parts and the vertical parts separately.

Key facts

  • The set of complex numbers contains all real numbers and all imaginary numbers.
  • Two complex numbers are equal only when their real parts and imaginary parts both match.
  • Addition works like vector addition on the complex plane.
  • Quadratics with a negative discriminant have complex solutions.

Complex Number example

Problem

Let \(z = 3 + 5i\) and \(w = -7 + 2i\). Find \(z + w\), then find the product \((2 + 3i)(4 – 5i)\).

  1. Add the real parts and the imaginary parts: \((3 – 7) + (5 + 2)i = -4 + 7i\).

  2. Multiply: \((2 + 3i)(4 – 5i) = 8 – 10i + 12i – 15i^2\).

  3. Replace \(i^2\) with \(-1\): \(8 + 2i + 15 = 23 + 2i\).

The sum is \(-4 + 7i\) and the product is \(23 + 2i\).

Common mistake

Watch out

Zoe leaves the product as \(8 – 10i + 12i – 15i^2 = 8 + 2i – 15i^2\) and writes the answer as \(8 + 2i – 15i^2\).

Why it is wrong

The answer is not in standard form until \(i^2\) is replaced by \(-1\). Then \(-15i^2 = +15\), and the real parts combine: \(8 + 15 = 23\). The final form is \(23 + 2i\).

Related terms and lessons

Browse the glossary: A–Z list · Algebra 2 vocabulary · Numbers and Operations

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