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Vertex Form

Vertex Form – definition and example, Algebra 1 math glossary – Mathovore

Key takeaway: Vertex form writes a quadratic as y = a(x − h)² + k, so the vertex (h, k), the direction and the width of the parabola can be read straight from the equation.

Grade 9 – Algebra 1A-SSE.B.3bFunctions and Graphs

Definition of Vertex Form

Definition

Vertex form is the version of a quadratic that shows its turning point. In \(y = a(x – h)^{2} + k\), the numbers \(h\) and \(k\) are the coordinates of the vertex, and \(a\) is the same stretch factor as in standard form. The graph is the basic parabola \(y = x^{2}\) moved right \(h\) units, up \(k\) units and stretched or flipped by \(a\).

Because the squared part is never negative, the sign of \(a\) tells whether \(k\) is the minimum (\(a > 0\)) or the maximum (\(a < 0\)). The form is especially helpful for sketching a graph quickly and for solving optimization problems. To use it for zeros, set \(y = 0\) and take square roots.

Formula and notation

The vertex form with vertex \((h, k)\) is

\[y = a(x – h)^{2} + k\]

Notice the minus sign inside the parentheses: \(y = (x + 4)^{2}\) has \(h = -4\), since \(x + 4 = x – (-4)\). The axis of symmetry is \(x = h\).

vertex (6, 9)(0, −9)y = −½(x − 6)² + 9
The equation shows the vertex (6, 9) at once; the negative a opens the parabola downward.

Key facts

  • The vertex is (h, k); the h value has the opposite sign from what appears in the parentheses.
  • If a is negative, the parabola opens downward.
  • Larger absolute values of a make a narrower parabola.
  • Expanding the square and combining terms converts vertex form to standard form.

Vertex Form example

Problem

For \(y = -\frac{1}{2}(x – 6)^{2} + 9\), find the vertex, the direction of opening, the \(y\)-intercept and the zeros.

  1. Compare with \(a(x – h)^{2} + k\): \(a = -\frac{1}{2}\), \(h = 6\), \(k = 9\). The vertex is \((6, 9)\) and it opens downward.

  2. Put \(x = 0\): \(-\frac{1}{2}(36) + 9 = -9\), so the \(y\)-intercept is \((0, -9)\).

  3. Put \(y = 0\): \((x – 6)^{2} = 18\), so \(x = 6 \pm 3\sqrt{2}\), about 1.76 and 10.24.

Vertex \((6, 9)\), opens down, \(y\)-intercept \(-9\), zeros \(6 \pm 3\sqrt{2}\).

Common mistake

Watch out

From \(y = (x + 4)^{2} – 13\), Tia states that the vertex is \((4, -13)\).

Why it is wrong

The pattern is \(x – h\). Since \(x + 4 = x – (-4)\), the value of \(h\) is \(-4\), so the vertex is \((-4, -13)\). Check by substituting \(x = -4\): the squared part is 0 and \(y = -13\), the lowest point.

Related terms and lessons

Browse the glossary: A–Z list · Algebra 1 vocabulary · Functions and Graphs

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