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Vertex of a Parabola

Vertex of a Parabola – definition and example, Algebra 1 math glossary – Mathovore

Key takeaway: The vertex of a parabola is its turning point, the highest or lowest point on the curve, located at x = −b/(2a) for a quadratic in standard form.

Grade 9 – Algebra 1F-IF.C.8aFunctions and Graphs

Definition of Vertex of a Parabola

Definition

The vertex of a parabola is the point where the curve changes direction. On an upward-opening parabola it is the minimum point, and on a downward-opening one it is the maximum point. It lies on the axis of symmetry, exactly halfway between the two x-intercepts when they exist.

The vertex answers optimization questions: the greatest height of a thrown ball, the lowest cost of a production run, the price that gives the most profit. To find it from standard form, first compute the \(x\)-coordinate with a formula, then substitute that value back into the function to get the \(y\)-coordinate.

Formula and notation

The vertex of a parabola given by \(y = ax^{2} + bx + c\) is the point \((h, k)\) with

\[h = -\frac{b}{2a}, \qquad k = f(h)\]

In vertex form \(y = a(x – h)^{2} + k\), the vertex can be read directly: \((h, k)\).

vertex (3, −11) = lowest pointy = 2x² − 12x + 7x = 3
The graph never goes below −11, the y-coordinate of the vertex.

Key facts

  • The vertex is the minimum if a is positive and the maximum if a is negative.
  • Its x-coordinate is the same as the line of symmetry.
  • Find the y-coordinate by substituting the x-coordinate into the function.
  • Shifting the vertex of a parabola translates the whole graph with it.

Vertex of a Parabola example

Problem

Find the vertex of \(f(x) = 2x^{2} – 12x + 7\) and say whether it is a minimum or a maximum.

  1. Identify \(a = 2\) and \(b = -12\). Then \(h = -\frac{-12}{2(2)} = \frac{12}{4} = 3\).

  2. Substitute: \(f(3) = 2(9) – 12(3) + 7 = 18 – 36 + 7 = -11\).

  3. Since \(a = 2 > 0\), the parabola opens upward.

The vertex is \((3, -11)\), a minimum.

Common mistake

Watch out

Lucia uses \(h = \frac{b}{2a}\) and gets \(\frac{-12}{4} = -3\), then reports the vertex as \((-3, 61)\).

Why it is wrong

The formula starts with a minus sign: \(h = -\frac{b}{2a}\). With \(b = -12\), the two negatives make a positive, giving \(h = 3\). Her point \((-3, 61)\) is on the graph but is far above the low point; the minimum value is \(-11\).

Related terms and lessons

Browse the glossary: A–Z list · Algebra 1 vocabulary · Functions and Graphs

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