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Arithmetic Sequence

Arithmetic Sequence – definition and example, Algebra 1 math glossary – Mathovore

Key takeaway: An arithmetic sequence is a list of numbers that climbs or falls by one constant amount at every step, and that amount is its common difference.

Grade 9 – Algebra 1F-IF.A.3Functions and Graphs

Definition of Arithmetic Sequence

Definition

In an arithmetic sequence, the gap between neighbors never changes. The sequence 17, 25, 33, 41 goes up by 8 every time, and 90, 84, 78 goes down by 6 every time. That fixed gap is the common difference \(d\).

Because each step adds the same amount, an arithmetic sequence behaves like a linear function whose inputs are counting numbers. Its graph is a set of separate dots lying on a straight line with slope \(d\). The opening term is named \(a_1\), and a distant term can be reached without writing out everything in between.

Formula and notation

Start at the first term and add \(d\) a total of \(n – 1\) times to reach position \(n\):

\[a_n = a_1 + (n – 1)d\]

To get \(d\), subtract a term from the next one. An arithmetic sequence may also be written step by step as \(a_{n+1} = a_n + d\).

1725334149n = 1n = 2n = 3n = 4n = 5+8+8+8+8
Every bar is 8 taller than the one before it, so the common difference is 8.

Key facts

  • The common difference can be positive, negative or zero.
  • Subtracting neighboring terms always gives the same number d.
  • Its graph is points on a line, so the rule is a linear function of n.
  • Starting at the term number n = 1 means the formula uses n minus 1 jumps.

Arithmetic Sequence example

Problem

A theater has 17 seats in row 1, 25 seats in row 2, 33 in row 3, and the pattern continues. How many seats are in row 30?

  1. Common difference: \(25 – 17 = 8\), and \(33 – 25 = 8\). The first term is \(a_1 = 17\).

  2. Write the rule: \(a_n = 17 + (n – 1)(8)\).

  3. Put \(n = 30\): \(a_{30} = 17 + 29(8) = 17 + 232 = 249\).

Row 30 has 249 seats.

Common mistake

Watch out

Using the same pattern, Brent writes \(a_n = 17 + 8n\) and finds \(a_{30} = 17 + 240 = 257\).

Why it is wrong

That rule gives \(a_1 = 25\), not the real first row of 17, because it adds 8 once too often. From row 1 to row 30 there are only 29 jumps, so use \(n – 1\): \(17 + 29(8) = 249\).

Related terms and lessons

Browse the glossary: A–Z list · Algebra 1 vocabulary · Functions and Graphs

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